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25x^2/5x=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
25x^2=0
a = 25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·25·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{50}=0$
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